C primer Plus Chap 05
C primer Plus Chap 05
C primer Plus 第五章代码与练习记录。
运算符、表达式和语句
- fx1.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12#include <stdio.h>
int main(void)
{
int x, y;
// x = (2+3) * 6;
// x = (12+6)/2*3;
// y = x = (2+3)/4;
y = 3 + 2*(x = 7/2);
printf("x = %d, y = %d.\n", x, y);
return 0;
}1
x = 3, y = 9. - fx2.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13#include <stdio.h>
int main(void)
{
int x;
// x = (int)3.8 + 3.3;
// x = (2+3)*10.5;
// x = 3/5*22.0;
x = 22.0 * 3 / 5;
printf("x = %d.\n", x);
return 0;
}1
x = 13. - fx3.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17#include <stdio.h>
#include <float.h>
int main(void)
{
int i = 0;
float n;
printf("watch out! here come a bunch of fractions!\n");
while (i++ < 30)
{
printf("%d\t", i);
n = 1.0 / i;
printf("%f\t",n);
}
printf("that's all, folks!\n");
return 0;
}1
1 1.000000 2 0.500000 3 0.333333 4 0.250000 5 0.200000 6 0.166667 7 0.142857 8 0.125000 9 0.111111 10 0.100000 11 0.090909 12 0.083333 13 0.076923 14 0.071429 15 0.066667 16 0.062500 17 0.058824 18 0.055556 19 0.052632 20 0.050000 21 0.047619 22 0.045455 23 0.043478 24 0.041667 25 0.040000 26 0.038462 27 0.037037 28 0.035714 29 0.034483 30 0.033333 that's all, folks! - fx4.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21#include <stdio.h>
#define S_TO_M 60
int main(void)
{
int sec, min, left;
printf("this program converts seconds to minutes and seconds.\n");
printf("just enter the number of seconds.\n");
scanf("%d", &sec);
printf("the sec is %d\n", sec);
while(sec>0)
{
min = sec / S_TO_M;
left = sec % S_TO_M;
printf("%d sec is %d min and %d sec.\n", sec, min, left);
printf("please enter the number of seconds:\n");
scanf("%d", &sec);
}
printf("bye!\n");
return 0;
}1
2
3
4
5
6
7
8this program converts seconds to minutes and seconds.
just enter the number of seconds.
123
the sec is 123
123 sec is 2 min and 3 sec.
please enter the number of seconds:
0
bye! - fx5.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13#include <stdio.h>
#define FORMAT "%s! C is cool!\n"
int main(void)
{
int num = 10;
printf(FORMAT, FORMAT);
printf("%d\n", ++num);
printf("%d\n", num++);
printf("%d\n", num--);
printf("%d\n", num);
return 0;
}1
2
3
4
5
6%s! C is cool!
! C is cool!
11
11
12
11 - xf6.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15#include <stdio.h>
int main(void)
{
char c1, c2;
int diff;
float num;
c1 = 'S';
c2 = '0';
diff = c1 - c2;
num = diff;
printf("%c%c%c: %d %3.2f\n", c1, c2, c1, diff, num);
return 0;
}1
S0S: 35 35.00 - fx7.c输出结果：
1
2
3
4
5
6
7
8
9
10
11#include <stdio.h>
#define TEN 10
int main(void)
{
int n = 0;
while(n++ < TEN)
printf("%5d", n);
printf("\n");
return 0;
}1
1 2 3 4 5 6 7 8 9 10 - fx8.c输出结果：
1
2
3
4
5
6
7
8
9
10#include <stdio.h>
int main(void)
{
int a = 96;
while(a++ < 103)
printf("%5c", a);
printf("\n");
return 0;
}1
a b c d e f g - fx9.c输出结果：
1
2
3
4
5
6
7
8
9#include <stdio.h>
int main(void)
{
int x = 0;
while(++x < 3)
printf("%4d", x);
printf("\n");
return 0;
}1
1 2 - fx9b.c输出结果：
1
2
3
4
5
6
7
8
9
10#include <stdio.h>
int main(void)
{
int x = 100;
while(x++ < 103)
printf("%4d\n", x);
printf("%4d\n", x);
return 0;
}1
2
3
4101
102
103
104 - fx9c.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12#include <stdio.h>
int main(void)
{
char ch = 's';
while(ch < 'w')
{
printf("%c\t", ch);
ch++;
}
printf("\n");
return 0;
}1
s t u v - fx10.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13
14#include <stdio.h>
#define MESG "COMPUTER BYTES DOG"
int main(void)
{
int n = 0;
while(n<5)
{
printf("%s\n", MESG);
n++;
}
printf("that's all.\n");
return 0;
}1
2
3
4
5
6COMPUTER BYTES DOG
COMPUTER BYTES DOG
COMPUTER BYTES DOG
COMPUTER BYTES DOG
COMPUTER BYTES DOG
that's all. - xt1.c输出结果：
1
2
3
4
5
6
7
8
9
10
11#include <stdio.h>
int main(void)
{
int x;
printf("please enter a number:\n");
scanf("%d", &x);
x = x + 10;
printf("%d\n", x);
return 0;
}1
2
3
4
5
6
7
8
9please enter number of nimutes:
26
26 minutes is about 0 hour and 26 minutes
please enter number of nimutes:
160
160 minutes is about 2 hour and 40 minutes
please enter number of nimutes:
0
done! - xt2.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13#include <stdio.h>
int main(void)
{
int number, count;
printf("please enter a number:\n");
scanf("%d", &number);
count = number + 10;
while(number++ <= count)
printf("%d\t", number-1);
printf("\n");
return 0;
}1
2
3please enter a number:
12
12 13 14 15 16 17 18 19 20 21 22 - xt3.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19#include <stdio.h>
int main(void)
{
const D_TO_W = 7;
int day, week, left;
printf("please enter the days:\n");
scanf("%d", &day);
while(day > 0)
{
week = day / D_TO_W;
left = day % D_TO_W;
printf("%d days are %d weeks, %d days.\n", day, week, left);
printf("please enter the days:\n");
scanf("%d", &day);
}
printf("done!\n");
return 0;
}1
2
3
4
5
6
7
8
9please enter the days:
7
7 days are 1 weeks, 0 days.
please enter the days:
26
26 days are 3 weeks, 5 days.
please enter the days:
0
done! - xt5.c输出结果：
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22#include <stdio.h>
void cubed(float n);
int main(void)
{
float number;
printf("enter 0 to quit the programe.\n");
printf("please enter a number:\n");
scanf("%f", &number);
while(number > 0)
{
cubed(number);
printf("please enter a number:\n");
scanf("%f", &number);
}
printf("the end!\n");
}
void cubed(float n)
{
printf("%.6f's cubed is %.6f.\n", n, n*n*n);
}1
2
3
4
5
6
7enter 0 to quit the programe.
please enter a number:
2
2.000000's cubed is 8.000000.
please enter a number:
0
the end!
C primer Plus Chap 05
https://ywmy.xyz/2022/05/14/C-primer-Plus-Chap-05/